Putting it Together with some Math:

From the previous Gear Ratio discussion, we know we can easily plot a graph of expected rate of fire vs all available gear ratios, as long as we know the motor output RPM. From the Motor Loading discussion, we also know that we can easily determine the motor output RPM by consulting the motor torque/speed graph plotted from a motor's maximum speed and torque ratings, as long as we know the load the motor is seeing. Putting these two facts together mathematically, we can arrive at a formula for expected rate of fire given a motor torque load and gear ratio.

ROF = motor output RPM/gear ratio
EG1000 output RPM = (27552/1407)*(1407 – motor torque load)

Combining the formulas above we get:

Expected ROF with EG1000 = ((27552/1407)*(1407 – motor torque load))/gear ratio

Since the torque load the motor sees varies with the ratio of the gear train between the motor and the loading components of the mechbox, we must isolate the effect of the gearset from the motor torque load and determine the “mechbox torque load” so that we can predict the rate of fire given different gear ratios. This can easily be incorporated into the equation because:

mechbox torque load = motor torque load*gear ratio

With a little more algebra, we derive our final equation:

Expected ROF with EG1000 = ((27552/1407)*(1407 – (mechbox torque load/gear ratio)))/gear ratio